The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
Answer:
you use the pythagorean theorem
Step-by-step explanation:
P.S. im not doing your hw
Answer:
x = 6
Step-by-step explanation:
EG = 59
EF = 8x - 14
FG = 4x + 1
to find the value of x
EF + FG = EG (same line)
8x - 14 + 4x + 1 = 59
12x -13 = 59
12x = 59 + 13
12x = 72
x = 72 ÷ 12
x = 6
You can even cross check for correct answer
EF + FG = EG
instead of x place the x's value we got
8x - 14 + 4x + 1 = 59
8 (6) - 14 + 4 (6) + 1 = 59
48 - 14 + 24 + 1 = 59
34 + 25 = 59
59 = 59
CROSS - CHECKED
