Erite 2 • 2•2 •2• 2 • 3•3•3• 3 in exponential form?

Please help!! <br><br> Take a factor out of the square root:

Doss [256]

Answer:

2a times the sq root of 2a or 2a (2a)**1/2

Step-by-step explanation:

(8a**3)**1/2 =

((2**2 * 2) (a**2) (a))**1/2 then take out and squares

2a (2a)**1/2

or 2a times the sq root of 2a

7 0

2 years ago

The number of girls in Mrs. Manning’s classes was 12 less than twice the number of boys. She had a total of 108 students in her

FromTheMoon [43]

40 boys and 68 girls

let's start with variables and an equation.

boys: x

girls: 2x - 12

and we know that boys and girls make up the class. so let's add the two expressions.

x + 2x - 12 = 108

3x - 12 = 108

+ 12 + 12

3x = 120

x = 40 boys

BUT x is only the number of BOYS in the class. so we have to find girls now. let's plug in our value of x into the girls' equation.

2x - 12 = # of girls

2(40) -12 = # of girls

80 - 12 = # of girls

68 girls

let's check our answer!

68 + 40 does in fact add to 108, therefore our answer is correct.

4 0

2 years ago

A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th

ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\$

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

$H_0: \mu=500\\\\H_a:\mu< 500$

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0

2 years ago

One canned orange juice is 25% orange juice another is 5% orange juice. How many liters of each should be mixed together in orde

Cerrena [4.2K]

Answer:

$X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y$ (3)

Replcaing equation (3) into equation (2) we got:

$0.75(6.4 -0.2 Y) +0.95 Y = 18.4$

And solving for Y we got:

$4.8 -0.15 Y +0.95 Y = 18.4$

$0.8 Y = 13.6$

$Y = 17$

And solving for X from equation (3) we got:

$X= 6.4 -0.2*17 = 3$

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

Step-by-step explanation:

For this problem we can work with the concentration of water and orange juice.

Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content

Using the concentration of orange juice we have:

$0.25 X + 0.05 Y = 20*0.08$ (1)

And for the water we have:

$0.75 X + 0.95Y = 20*0.92$ (2)

If we solve for X from equation (1) we got:

$X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y$ (3)

Replcaing equation (3) into equation (2) we got:

$0.75(6.4 -0.2 Y) +0.95 Y = 18.4$

And solving for Y we got:

$4.8 -0.15 Y +0.95 Y = 18.4$

$0.8 Y = 13.6$

$Y = 17$

And solving for X from equation (3) we got:

$X= 6.4 -0.2*17 = 3$

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

7 0

3 years ago

What is the slope and y-intercept of the line represented by 3x=15

Svetach [21]

Answer:

The slope is undefined and there is no y- intercept

Step-by-step explanation:

The line is equivelent to x=5

This is a vertical line so the slope is undefined and there is no y- intercept

8 0

3 years ago

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