For statictics of Out of 780 smokers, 376 have been divorced, Non-smokers: Out of 2855 non-smokers, 902 have been divorced, the 95% confidence interval for smokers and non-smokers is mathematically given as
- 95% confidence interval = (0.5352, 0.4462)
- 95% confidence interval = (0.3424, 0.2894)
- 53% increased risk of divorce for smokers.
<h3>What is the 95% confidence interval for smokers and non-smokers?</h3>
Generally, the equation for the Confidence interval is mathematically given as
p ± Z/2[p(1-p)]/n
Where
Z1/2=1-(0.05/2)
Z1/2=0.975
Read z table we have
Z score= 1.96
Hence
0.4907 ± 1.96 (0.4907)(1-0.4907)/485
0.4907±0.0445
Therefore
95% confidence interval = (0.5352, 0.4462)
b)
Z1/2 = 1- (0.05/2)
Z1/2 = 0.975
Z score= 1.96
0.3159 ± 1.96 (0.3159)(1-0.3159)/1184
0.3159±0.0265
Thereofore
95% confidence interval = (0.3424, 0.2894)
c)
In conclusion, The 95% confidence interval helps us read that 53% increased risk of divorce for smokers.
Read more about Confidence interval
brainly.com/question/17097944
The answer is "The empty square has a side length of 10 and an area of 100 square units"
Answer:
It is not possible
Step-by-step explanation:
First 6 people have 9 friends and since 6 people can have totally the same friends which could all be each other, we would have 5 friends(from same 6 people) + 4 friends(not from the 6). Therefore we would have total 9 people/students
In second group of 8 people, their friends could entirely be the same be the same as the first group's friends or they could all be each other's friend hence just an additional 8 students to the population
In the third group of 11 people/students, same thing could apply as above but total number of students would always surpass 25 with the additional population. Example 9+8+11= 28
Therefore it is not possible that 25 students would each have those number of friends.
