Answer:
The speed of the jet is 347 mph and the speed of the wind is 18 mph.
Step-by-step explanation:
We have the following:
x = the speed of the jet in still air.
y = the speed of the wind
we know that the speed is equal to:
v = d / t
therefore the distance would be:
d = v * t
if we replace with the information of the exercise we have:
3 * (x + y) = 1095
3 * (x - y) = 987
we must solve this system of equations, add both equations and we are left:
3 * x + 3 * y = 1095
3 * x - 3 * y = 987
3 * x + 3 * y + 3 * x - 3 * y = 1095 + 987
6 * x = 2082
x = 2082/6 = 347
now to calculate y, we replace:
3 * (347 + y) = 1095
1041 + 3 * y = 1095
3 * y = 1095 - 1041
y = 54/3 = 18
The speed of the jet is 347 mph and the speed of the wind is 18 mph.
The answer is 20.3 miles per hour. First, you need to change meter and second to mile and hour. The 100 meter equals 100/1609 mile. 11 seconds equals 11/3600 hour. Then using mile number divides by hour you can get the answer.
15.90 would be your new answer
Answer:
Step-by-step explanation:
3x-2=-1
3x = -1 + 2
3x = 1
x = 1/3
Answer:
(344*20) + ( 2*20) = (20*2) = ?
Step-by-step explanation: