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olchik [2.2K]
3 years ago
14

WILL GIVE BRAINLIEST!!

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
The easiest way to do this is to plug everything in the left side and see what equals 10, but you could also solve for c (which I will show you).
2c+5(c-5)=10
2c+5c-25=10
7c-25=10
7c=35
c=5
maks197457 [2]3 years ago
3 0
I say the answer is 5
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(3y^0 x^2)^6 times y^-3 zx8
timurjin [86]
Ok so some basic rules

(x^m)(x^n)=x^{m+n}
(ab)^c=(a^c)(b^c)
(x^m)^n=x^{mn}
x^0=1
x^{-m}= \frac{1}{x^m}

so
[(3y^0x^2)^6][y^{-3}zx^8]
[(3(1)x^2)^6][y^{-3}zx^8]
[(3x^2)^6][y^{-3}zx^8]
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(3^6)(x^{12})(y^{-3})(z)(x^8)
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3 0
3 years ago
Given that RT ≅ WX, which statement must be true?
wel
The length of TR<span> ≅ The length of XW</span>
4 0
3 years ago
Can someone please help me real quick?​
Ivahew [28]

Answer:

Big square - unshaded = shaded

((8+4)X(10+5))-(10X8)=100

Answer: 100

Step-by-step explanation:

8 0
2 years ago
Mike is building a rectangular dog pen the length of the pen is 20 feet greater than its with w
Temka [501]

Answer:

f(W)=W^{2} +20W

Step-by-step explanation:

we know that

The area of a rectangle is equal to

A=LW -----> equation A

we have

L=W+20 -----> equation B

substitute the equation B in equation A

A=(W+20)W

Rewrite as a function

f(W)=(W+20)W

f(W)=W^{2} +20W

5 0
3 years ago
A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base
zaharov [31]

Okay so the equation you need to use is (x2/a2)+(y2/b2)-(z2/c2)=1

So an equation describing the shape of the tower in the coordinates where the origin is at the center of the narrowest part of the tower would be:

<span>x^2 / 100^2 + y^2 / 100^2 – z^2 / 2 * 100^2 = 1</span>

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0
3 years ago
Read 2 more answers
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