Answer:
10
Step-by-step explanation:
The question is wrong it should be 5C3
5C3=5!/((5-3)!•3!)=5!/(2!•3!)
=(5•4•3•2•1)/(2•1•3•2•1)
=10
We know,
sin(x) and cos(x) have minimum value equal to -1 and maximum value is 1.
Maximum value of sin(x) is 1
So we replace sin by 1 in our given equation

When we replace sin by 1 we will get

y= -2+5 = 3
So maximum value is 3
Answer:
magnitude is always postive
so, it will be +2.5 , so C
Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
Answer:
1/20
Step-by-step explanation:
Step 1: Write the given number as the numerator and place 1 in the denominator right below the decimal point followed by the number of zeros required accordingly.
In this case, 0.05 has two numbers after the decimal, so, we place 100 in the denominator and remove the decimal point. This will make it 5/100
Step 2: Then, this fraction can be simplified. 5/100 = 1/20
Thus, 0.05 as a fraction is written as 1/20