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KonstantinChe [14]
3 years ago
11

Which solution eliminates the need for dedicated high-speed WAN connections between sites

Computers and Technology
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

Wireless WAN like VSAT and WIMAX.

Explanation:

WAN or wide area network is a form of network meant for long distance communication between sites. It is made up of interconnecting local area networks spanning from a town to global communication of branches in an organisation.

For local area networks to be connected together to make a WAN, a dedicated high speed cable connection must be installed between sites. Fiber optics, among others, is the widely used dedicated WAN backbone connection. Cable connections are faster and moderately secure.

A VSAT is a wireless network connection method, where networks are connected using satellite dishes in remote networks, in the line of sight to a satellite, for WAN communication. It is not as fast or as secure as the cable connection, but can be used in remote area, where ISP in not available.

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shutvik [7]
It lets them reach out to people on that platform that can advertise their products
4 0
3 years ago
Explain the role of ICT in banks​
vladimir1956 [14]

Answer: ICT help banks improve the efficiency and effectiveness of services offered to customers, and enhances business processes, managerial decision making, and workgroup collaborations, which strengthens their competitive positions in rapidly changing and emerging economies.

Explanation: please give branliest I only need one more to make ace

7 0
3 years ago
Write an expression using Boolean operators that prints "Special number" if special_num is -99, 0, or 44.
gulaghasi [49]

Answer:

special_num = int(input())

if  special_num == -99 or special_num == 0 or special_num == 44:

   print('Special number')

else:

   print('Not special number')

Explanation:

#get input

special_num = int(input())

#if function to evaluate true or false(aka Boolean)

if  special_num == -99 or special_num == 0 or special_num == 44:

#true evaluation

print('Special number')

#false evaluation

print('Not special number')

8 0
3 years ago
i have a bag of trail mix . one half of the bag is peanuts. 1/4 of the bag is chocolate candies , and 1/4 of the bag is died fru
Lelu [443]
In our bag, 1/2 is peanuts, 1/4 is chocolate and 1/4 is dried fruit.

The likelihood of drawing a chocolate therefore is 1/4. 

The likelihood of drawing a peanut is 1/2 and the likelihood of drawing a dried fruit is 1/4.

Thus, D is the correct answer because the 1/4 likelihood of drawing a chocolate is less than the 1/2 chance of drawing a peanut.
8 0
3 years ago
Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has
OLEGan [10]

Answer:

#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

   int n = 5;

   int j=1;

   // for loop

   for(;j<=n;j++){

       cout<<"*";  //print the '*'

   }

}

Explanation:

Create the main function and declare the variable n with the value 5 and initialize the variable j with zero.

take a for loop for executing the statement again and again until a condition is not false.

Syntax for loop:

for(initialize; condition; increment/decrement)

{

 statement;

}  

we can initialize the variable outside as well but the semicolon always present in the loop otherwise compiler gives the error.

for example:

int i=0;

for(; i<4; i++){

  statement;

}

The condition put in the original code is j <= n and n has the value 5. so, the loop executes 5 times and inside the loop, write the print statement for print the character '*'.

6 0
4 years ago
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