All categories

3 years ago

What is the solution of |9x - 36| = 9

Mathematics

1 answer:

mash [69]3 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

1. |9x - 36| = 9

2. Add 36 to each side.

3. |9x| = 45

4. Divide 9 on both sides.

5. |x| = 5

6. Absolute Value of x.

7. x = 5

8. Theres your answer :)

You might be interested in

Suppose a set of data about the spread (in hundreds of acres) of a food-borne bacteria (after t weeks) in lettuce has the follow

Alexxandr [17]

Answer:

A sinusoidal model would be used

The kind of function that have consistency in the periodic rate of change is the Average rate of changes

Step-by-step explanation:

The type of model that would be used is sinusoidal model and this is because there is periodic change in the values given ( i.e the rate of changes given )

For percentage rate of changes :

starting from 0.9% there is an increase to 1.3% then a decrease to 1.1% and a further decrease to 1% before an increase to 1.3% and another decrease to 1%

For Average rate of changes:

starting from 2.9 there is a decrease to 2.4, then an increase to 3.7 and another decrease to 3.1 followed by an increase to 3.6 and a decrease back to 3.2

This relation ( sinusoidal model ) is best suited for a linear model because there is a periodic rate of change in the functions

The kind of function that have consistency in the period rate of change is the Average rate of changes

6 0

4 years ago

1. What number is 27% of 52?

Goshia [24]

14 or 14.04 if you want to be more specific

8 0

3 years ago

Read 2 more answers

Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−

poizon [28]

$f(t)=\begin{cases}\cos t&\text{for }0\le t$

The Laplace transform is then

$\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt$

Let $I$ denote the integral we want to compute. Integrating by parts, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t$

gives

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt$

Integrate by parts again, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t$

Then

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)$

$I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I$

$(s^2+1)I=s(e^{-\pi s}+1)$

$I=\dfrac s{s^2+1}(e^{-\pi s}+1)$

7 0

3 years ago

Question 2 of 10

Jet001 [13]

Given:

The parent function is:

$f(x)=x^2$

This function shift 1 unit left, vertically stretch by a factor of 3 and reflected over the x-axis.

To find:

The function after the given transformations.

Step-by-step explanation:

The transformation is defined as

$g(x)=kf(x+a)+b$ ... (i)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If k<0, then the graph of f(x) is reflected over the x-axis.

If 0<|k|<1, then the graph compressed vertically by factor |k| and if |k|>1, then the graph stretch vertically by factor |k|.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

It is given that the graph of f(x) shifts 1 unit left, so a=1.

The graph of f(x) vertically stretch by a factor of 3, so |k|=3.

The graph of f(x) reflected over the x-axis, so k=-3.

There is no vertical shift, so b=0.

Putting $a=1,k=-3,b=0$ in (i), we get

$g(x)=-3f(x+1)+0$

$g(x)=-3f(x+1)$

$g(x)=-3(x+1)^2$ $[\because f(x)=x^2]$

Therefore, the correct option is B.

5 0

3 years ago

If you apply the changes below to the linear parent function, Fx) = x, what is

Inga [223]

Answer: A. G(x)= ax=y= - f(x) is flip over x-axis. Therefore, f(x) =14x would become f(x) =-14x. Therefore, final transformed function f(x)=-14x is vertically stretch by a factor of 14 and flip over the x-axis.

5 0

4 years ago