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sergij07 [2.7K]
4 years ago
13

Ming plays video games online. When he signed up with the game site, Ming got 200200 points. Ming earns 2020 more points for eac

h hour that he plays. How many hours does Ming have to play to get to 500500 points?
Mathematics
1 answer:
larisa86 [58]4 years ago
6 0

It will take 148\frac{67}{101} hours (In decimal form its 148.66336633)


500500-200200=300300

300300÷2020=148.66336633

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2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10

n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15



3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10

t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1


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5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}

v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45


3 0
3 years ago
What’s 6 x 5 * divide* 10? I need answers plz
Reika [66]

Answer:

It is 3

Step-by-step explanation:

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30/10= 3

Mark me Brainliest?

3 0
3 years ago
Read 2 more answers
Due in half an Hour. Thanks for your help.
Alecsey [184]

Answer:

C and $320.45

Step-by-step explanation:

I think it's C because this is the full function :

b = 26 \times d + 3.5 \times 13 + 14.95

And to get the b part of the question i just put the number in

b = 26 \times 10 + 3.5 \times 13 + 14.95 = 320.45

I'm not a 100% sure, sorry if it's wrong

7 0
3 years ago
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