All categories

3 years ago

If you roll two dice, what is the probability that the numbers add to 7? Why?

Mathematics

2 answers:

juin [17]3 years ago

7 0

Answer:

1/6

Step-by-step explanation:

possible combinations are = 1-6,2-5,3-4,4-3,5-2,6-1

so probability= 6 * 1/36 = 1/6

Vinil7 [7]3 years ago

4 0

Answer:

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is 6/36 = 1/6.

Step-by-step explanation:

You might be interested in

Please Hurry ...Which expression is equivalent to

swat32

Answer:

$\huge\boxed{\sf \frac{160rs^5}{t^6}}$

Step-by-step explanation:

$\sf 5r^6t^4 ( \frac{4r^3s^tt^4}{2r^4st^6} ) ^5$

Using rule of exponents $\sf a^m/a^n = a^{m-n}$

$\sf 5r^6t^4 ( 2 r^{3-4} s^{2-1}t^{4-6})^5\\5r^6t^4(2r^{-1}st^{-2})^5\\5r^6t^4 * 32 r^{-5}s^5t^{-10}$

Using rule of exponents $\sf a^m*a^n = a^{m+n}$

$\sf 160 r^{6-5}s^5t^{4-10}$

$\sf 160 rs^5 t^{-6}$

To equalize the negative sign, we'll move t to the denominator

$\sf \frac{160rs^5}{t^6}$

8 0

3 years ago

Pls help as soon as possible

alexgriva [62]

Answer:26 last one 25 first and 3 middle

Step-by-step explanation:

6 0

2 years ago

Bill has two fat cats. He feeds each cat 150 grams of dry food each, twice a day. If he buys a 5 kilogram bag of dry food, about

Alinara [238K]

Answer: 4 days (I think)

Step-by-step explanation:

One cat = 150*2 = 300g

Two cats = 600g

600*2 = 1200 (this is the total amount of food they both eat in a day)

5kg = 5000g

1200g/5000g = 4.17

The bag will last 4 days.

6 0

2 years ago

Best and correct answer gets brainliest!!!

dmitriy555 [2]

59 degrees!
because you set up your problem: 3c+2+2c-7=90
then combine all like terms: 5c-5=90
Add 5 to both sides: 5c=95
then divide both sides by 5: c=19
Plug in your answer: 3(19)+2=59

8 0

3 years ago

Can someone please solve this?

Molodets [167]

Multiplicity of a root means, is there that many times.

$\bf \begin{cases}
x=3\implies &x-3=0\\
x=2\implies 
&\begin{cases}
x-2=0\\
x-2=0\\
x-2=0
\end{cases}
\end{cases}
\\\\\\
(x-3)(x-2)~~(x-2)(x-2)=\textit{original polynomial}
\\\\\\
(x^2-5x+6)~~(x^2-4x+4)=y
\\\\\\
x^4-4x^3+4x^2-5x^3+20x^2-20x+6x^2-24x+24=y
\\\\\\
1x^4-9x^3+30x^2-44x+24=y$

3 0

3 years ago