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liubo4ka [24]
3 years ago
7

a triangular prism has a volume of 240 cubic meters.Which of the following are possible dimensions for the area of the base and

the height of the prism?
Mathematics
1 answer:
katovenus [111]3 years ago
3 0
I'm not sure of the choices, but I can still help you out. All of the possible dimensions are listed below:
1x240, 240x1, 2x120, 120x2, 80x3, 3x80, 4x60, 60x4, 5x48, 48x5, 6x40, 40x6, 8x30, 30x8, 10x24, 24x10, 12x20, 20x12, 15x16, 16x15

Hope this helped! If it did, please give me a good rating and mark me brainliest. Thanks!
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3 0
3 years ago
What would be the amount of his last monthly bill in order. The bill amount to be 110 for all 12 months
meriva
Add up all the numbers the divide by the amount of numbers in the set.
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8 0
2 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




8 0
3 years ago
The ratio of the length 2.0 meters to the length 1.2 meters is
photoshop1234 [79]

Answer:

The Ration of length 2.0 meters  to the length 1.2 meters = 5 : 3

Step-by-step explanation:

The given two length are 2.0 m  and 1.2 m

Length L1 = 2.0 m     And

Length L2 = 1.2 m

SO, The ratio of L1 : L2 = \frac{2.0}{1.2}

Or, The ratio of L1 : L2 =  \frac{20}{12}

∴    The ratio of L1 : L2 =  \frac{5}{3}

Hence The ratio of L1 : L2 is 5 : 3    Answer

4 0
3 years ago
Is (2, 3) a solution to the inequality y &gt; 6x + 3?
Sindrei [870]

Good morning

Answer:

NO

Step-by-step explanation:

Here we just substitute x and y by their values and see if the inequality still true or not

y = 3

6x + 3 = 6(2) + 3 = 15

since 3 < 15 then the inequality y > 6x + 3 is wrong.

______________________________________

:)

8 0
3 years ago
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