C3=n
N x 2 - 6 + 2
N < (6x8) - 10
First, isolate the decimal. second, put it over the correct denominator based on the decimal place: 96/100. Next, divide by a number that goes into both 96 and 100. 4 works.... 24/25. And that is your answer, after you add the original 2 back: 2
Total distance 5 km; at 5km / 0.65 h =
Second part distance: x; at 6 km/h, during t2
First part distance: 5 - x; at 8.75 km/h, during t1
V = d/t ⇒ t = d/V
t2 = x/6
t1=[5-x]/8.75
t2 + t1 = 0.65
x/6 + [5-x]/8.75 = 0.65
x/6 + 5/8.75 - x/8.75 = 13/20
x/6 - x/8.75 = 13/20 - 5/8.75
x/6 - 4x/35 =13/20 - 20/35
35x - 24x = (35*6)(35*13 - 20*20)/(20*35)
11 x = 16.5
x = 16.5/11 = 1.5 km
The triangles that would be created if the rectangle has a length and width that are different is a right scalene triangle.
It will have one right angle and all three sides of the triangle will be different lengths because the hypotenuse (the diagonal will be longer than the other two sides.
