Say her hourly pay was $p for the day shift and $1.2p for the night shift.
(1) x = 55. Clearly insufficient: we need to know how these 55 hours are split between the day shift hours and the night shift hour.
(2) Grace's gross pay for the hours she worked on day shift last month was exactly 50% of her total gross pay for last month. Not sufficient.
(1)+(2) Say Grace worked h hours on the day shift and 55-h hours on the night shift. Thus, her pay for the the hours she worked on day shift is $ph and the total gross pay is $ph+(55-h)*1.2p. From (2) we have that ph=0.5(ph+(55-h)*1.2p) --> reduce by p: h=0.5(h+(55-h)*1.2). We have 1 variable, so we can solve for it. Sufficient.
Answer: C.
The first value is -9, so f(1)=-9. Next, to find the common difference, we subtract the second number from the first number, getting -2-(-9)=7. Therefore, the common difference is 7
-14 = -5 + 3c
First, regroup your terms. / Your problem should look like:
Second, add 5 to both sides. / Your problem should look like:
Third, simplify -14 + 5 to -9. / Your problem should look like:
Fourth, divide both sides by 3. / Your problem should look like:
Fifth, simplify the fraction to 3. / Your problem should look like:
Sixth, switch your sides. / Your problem should look like:
Answer:
c = -3
Answer:
Step-by-step explanation:
when 1/2 inch equals 4 feet the room is 2.25 inches, then
2 1/4 = 8/4 + 1/4 = 9/4
9/4 inches is the scale distance of the room
each 1/2 inch is 4 feet so divide 9/4 by 1/2 then multiply that by 4 to find the distance of the room
9/4 ÷ 1/2 = 9/4
9/4 * 2/1 = 18/4
18/4 = 9/2
9/2 * 4 feet = 9/2 * 4/1
9/2 * 4/1 = 36/2
36/2=18
the room is 18 feet across
then if the scale is 2/3 of an inch is 4 feet , then
2/3 * 9/4 = 18/12
18/12 = 3 inches is the scale size of Quinto's room
Since there are 25 students and there’s 21 at the zoo you would end up having 21 out of 25 and 21 out of 25 as a percentage is 84% because you have to look at 25 as a whole and that whole would be 100% so 84 out of 100% is equal to 21 out of 25
