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3 years ago

In the formula d=/(x2-x1)^2+(y2-y1)^2 , how does each subtraction expression relate to the Pythagorean theorem?

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

I don't think you need this

Yuliya22 [10]3 years ago

5 0

Answer:

option A

Step-by-stevvp explanation:

In the formula $d=\sqrt{(x2-x1)^2+(y2-y1)^2}$

The formula is used to find the distance between two points

(x2-x1) gives the length of one leg

(y2-y1) gives the length of another leg

In a right angle triangle , Pythagorean theorem is $c=\sqrt{a^2 + b^2}$

where a and b represents the sides of the triangle

Each subtraction expression in the formula represents the leg of the right angle triangle with the hypotenuse of length d

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