30 divided by 5 is 6, so the other term is (x+6). (x+5)(x+6) becomes x^2+11x+30, so k is equal to 11.
Now we look at the common denominator.
It is x(x + 2)(x - 2).
x cannot be zero, -2 or 2 because that would cause a zero in the denominator.
Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.
Answer: x = 8
12 vertices are on the polyhedron
Answer:
74.30
Step-by-step explanation:
Let s = entry price for a student
Let t = entry price for a teacher
4s +5t = 95
6s+10t = 173
I will use elimination to solve this problem.
Multiply the first equation by -2
-2(4s +5t) = -2*95
Distribute
-8s - 10t = -190
Add this equation to the second equation to eliminate t
-8s - 10t = -190
6s+10t = 173
----------------------
-2s = -17
Divide by -2
-2s/-2 = -17/-2
s = 8.50
Now we need to find t
4s +5t = 95
Substitute s=8.50
4(8.50) +5(t) = 95
34 +5t = 95
Subtract 34 from each side
34-34 +5t = 95-34
5t = 61
Divide by 5
5t/5 = 61/5
t = 12.20
We want to find the cost for 3 students and 4 teachers
3s+4t
3(8.50) + 4(12.20)
25.50 + 48.80
74.30
