The side AB measures option 2. 
units long.
Step-by-step explanation:
Step 1:
The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).
The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.
To calculate the distance between two points, we use the formula 
where (
) are the coordinates of the first point and (
) are the coordinates of the second point.
Step 2:
For A (4, 5) and B (2, 1), () = (4, 5) and () = (2, 1). Substituting these values in the distance formula, we get
So the side AB measures units long which is the second option.
You can make it easier by replacing x^n with another variable, factoring, then putting x^n back in the end.
Using exponent and algebra rules, rewrite x^2n - 2x^n + 1 as
(x^n)^2 - (2 x x^2) + 1
Then, let x^n = m.
m^2 - 2m + 1
Now factor that: (m - 1)^2
And now put x^n back: (x^n - 1)^2
9514 1404 393
Answer:
a) ∠DAE = 33°; ∠ABD = 57°
b) ∠CEB = 90°
c) ∠ABE = 22°
d) ∠ADE = 15°
Step-by-step explanation:
The diagonals of a rhombus meet at right angles. Each bisects the corner angles at its ends. Adjacent angles are supplementary, opposite angles are congruent, and each diagonal creates two isosceles triangles.
a) ∠DAE = 90° - ∠ADE = 90° -57°
∠DAE = 33°
∠ADE = ∠ABD = 57°
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b) ∠CEB = 90° . . . . . the diagonals meet at right angles
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c) ∠ABE = 44°/2
∠ABE = 22°
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d) ∠ADE = 90° -(1/2)∠DAB = 90° -150°/2
∠ADE = 15°
Answer:
58.1 degrees
Step-by-step explanation:
Given the following
JK = 9.4miles (towards south) negative y axis
If the move 15.1 miles towards east (that will be towards the positive x axis)
Using the SOH CAH TOA identity
opposite= 15.1 miles(side facing m<J)
adjacent= JK = 9.4miles
tan theta = opposite/adjacent
tan m<J = 15.1/9.4
tan m<J = 1.6063
m<J = arctan (1.6063)
m<J = 58.09 degrees
Hence the measure of m<J to the nearest tenth is 58.1 degrees
I think is yes but I’m not sure
