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kozerog [31]
3 years ago
5

Over the last 6 days, you earned the following amounts raking leaves: $44, $34, $54, $55, $61, and $37. On the average, how much

did you earn a day?
Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

Answer: $47.50

Step-by-step explanation: Averages are calculated by adding all values up and dividing by # of values. Here the sum is 285, and 285/6=47.5

You might be interested in
What is the midpoint of the line segment with endpoints (-1,3) and (-5,5)?
andrew11 [14]

Answer:

(4, 5)

Step-by-step explanation:

Calculate the midpoint using the midpoint formula

midpoint = [( + ), ( + ) ]

with (,  ) = (1, 2) and (,  ) = (7, 8)

midpoint = [(1 + 7), (2 + 8) ]

              = (4, 5)

6 0
2 years ago
The number 6 is 30% of what number
alexandr402 [8]
6 and 3000 is the answer for ur question would be 3000
8 0
3 years ago
Can someone help me with this? I need to find the points of discontinuity/limits for each of these. I think one point is 4, but
Debora [2.8K]
The answers are shown in the attached image

-------------------------------------------------------------------------

Explanation:

Set the denominator x^4-8x^3+16x^2 equal to zero and solve for x

x^4-8x^3+16x^2 = 0
x^2(x^2-8x+16) = 0
x^2(x-4)^2 = 0
x^2 = 0 or (x-4)^2 = 0
x = 0 or x-4 = 0
x = 0 or x = 4

The x values 0 and 4 make the denominator zero

These x values lead to asymptote discontinuities because the numerator 8x-24 = 8(x-3) has no common factors which cancel with the denominator factors.

There are two vertical asymptotes

Let's see what happens when we plug in a value to the left of x = 0, say x = -1, we'd get
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(-1) = (8(-1)-24)/((-1)^4-8(-1)^3+16(-1)^2)
f(-1) = -1.28
So as x gets closer and closer to x = 0 from the left side, the f(x) is heading to negative infinity

Now plug in some value to the right of x = 0. I'm going to pick x = 1
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(1) = (8(1)-24)/((1)^4-8(1)^3+16(1)^2)
f(1) = -1.78 (approximate)
So as x gets closer and closer to x = 0 from the right side, the f(x) is heading to negative infinity

Overall, as x approaches 0 from either the left or right side of x = 0, the y value is heading off to negative infinity

---------------------

Repeat for values to the left and right of x = 4
We can't use x = 1 as it turns out that x = 3 is a root
But we can use something like x = 3.5 to find that...
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(3.5) = (8(3.5)-24)/((3.5)^4-8(3.5)^3+16(3.5)^2)
f(3.5) = 1.31 approx
So as x gets closer to x = 4 from the left, y is getting closer to positive infinity

Plug in x = 5 to find that
f(x) = (8x-24)/(x^4-8x^3+16x^2)
f(5) = (8(5)-24)/((5)^4-8(5)^3+16(5)^2)
f(5) = 0.64
which has the same behavior as the left side

So overall, as we approach x = 4, the y value is heading off to positive infinity

Again everything is summarized in the image attachment

Note: you could make a table of more values but they would effectively say what has already been said. It would be redundant busy work. However, its always good practice for function evaluation. 

6 0
3 years ago
A rectangle with an area of 5/8 ft² is dilated by a factor of 8. What is the area of the dilated rectangle?
gulaghasi [49]

Answer:

40 ft²

Step-by-step explanation:

Let the length of the original rectangle be L and original Breadth be B

it is given that the original area  is 5/8 ft²

i.e.

Original Length x Original Breadth = Original Area, or,

LB = 5/8 ft² ------------------(1)

Given that the dilation factor is 8,

Hence,

New Length = 8L and New Breadth = 8B

THerefore,

New Area = 8L x 8B

= 64 LB  (from (1) above , we know that LB = 5/8 ft², substitute into expression)

= 64 (5/8)

= 40 ft²

4 0
3 years ago
Given real numbers a,b > 1.
irina [24]

Answer:

FALSE

Step-by-step explanation:

Recall that a function f(x) is of exponential order c, if there exists a constant M such that and a real r such that

|f(x)|\leq Me^{cx}\;(x\geq r)

Now, take a = 2.5 and b = 2

The functions

f(x)=(2.5)^x\;g(x)=2^x

are both exponential of order 1, since  

\lim_{x \to \infty}\frac{f(x)}{e^x}=\lim_{x \to \infty}\frac{g(x)}{e^x}=0

but a>b

8 0
3 years ago
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