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3 years ago

Which of the following graphs could be a representation of a geometric sequence? Check all that apply

Mathematics

2 answers:

luda_lava [24]3 years ago

6 0

Answer:

the other person is right, the answers are A, B, and C

Step-by-step explanation:

Gala2k [10]3 years ago

4 0

Answer:

$\boxed{\text{A, B, and C}}$

Step-by-step explanation:

The formula for a geometric series is aₙ = a₁rⁿ⁻¹.

This is analogous to the exponential series y = a₀rⁿ.

The difference it that, in a geometric series, n must be positive.

Thus, the graph of a geometric series starts somewhere on the y-axis and either increases exponentially or decreases asymptotically to the x axis.

In Graph A , the successive values of y are 5/2⁰, 5/2¹, 5/2² and 5/2³. This is an example of exponential decay.

In Graph B, the successive values of y are 3¹, 3² and 3³. This is an example of exponential growth.

In Graph C, the successive values of y are 2¹, 2², 2³, and 2⁴, another example of exponential growth.

In Graph D, the successive values of y are 1, 2.5, 4, 5.5. and 7. There is a constant difference of 1,5, so this represents an arithmetic series.

$\boxed{\textbf{A, B, and C}}$ could represent a geometric series.

You might be interested in

Write a quadratic equation with roots of 3/4 and -4

Vaselesa [24]

A quadratic equation given roots is solved by using the relation

${x}^{2} - (sum \: of \: roots)x + product \: of \: roots$

from the question,

sum of the root will be

$\frac{3}{4} + ( - 4) = \frac{3}{4} - 4$

$= \frac{3 - 16}{4}$

$= \frac{ - 13}{4}$

and also, product of the roots will

$\frac{3}{4} \times ( - 4) = - 3$

now substituting the sum of roots and product of roots into the equation

${x}^{2} - ( - \frac{13}{4} )x - 3$

$= {x}^{2} + \frac{13}{4} x - 3$

as the quadratic equation for the root 3/4 and -4

4 0

3 years ago

BEST ANSWER GETS BRAINLIEST!!!!!!!!

Ad libitum [116K]

Answer:

(x + 6, y + 0), 180° rotation, reflection over the x‐axis

Step-by-step explanation:

The answer can be found out simply , a trapezoid has its horizontal sides usually parallel meanwhile the vertical sides are not parallel.

The horizontal parallel sides are on the x-axis.

Reflection over y- axis would leave the trapezoid in a vertical position such that the trapezoid ABCD won't be carried on the transformed trapezoid as shown in figure.

So option 1 and 2 are removed.

Now, a 90 degree rotation would leave the trapezoid in a vertical position again so its not suitable again.

In,The final option (x + 6, y + 0), 180° rotation, reflection over the x‐axis, x+6 would allow the parallel sides to increase in value hence the trapezoid would increase in size,

180 degree rotation would leave the trapezoid in an opposite position and reflection over x-axis would bring it below the Original trapezoid. Hence, transformed trapezoid A`B`C`D` would carry original trapezoid ABCD onto itself