Answer: point C = (3.75, 1.5)
Step-by-step explanation:
As the direction of the distance is from A to B, we need to down the y-axis and along (to the right) the x-axis.
Find the distance between the x-coordinates of both points by subtracting the x-coordinate of A from the x-coordinate of B:
5 - 0 = 5
3/4 of the length of this distance = 0.75 x 5 = 3.75
So the x-coordinate of C will be the sum of the distance (3.75) and the x-coordinate of A (as we are "travelling" from A to B):
3.75 + 0 = 3.75
Find the distance between the y-coordinates of both points by subtracting the y-coordinate of B from the y-coordinate of A:
3 - 1 = 2
3/4 of the length of this distance = 0.75 x 2 = 1.5
So the y-coordinate of C will be the y-coordinate of A minus the distance (1.5):
3 - 1.5 = 1.5
Therefore, point C = (3.75, 1.5)
Hope that helps - i dont know what u meant by option 1,2,3 so if u have an questions or i did it wrong i will fix it <3
When height turns to 3 times height or 3h
we can replace h with 3h and see what happens
A=1/2b(3h)
A=3/2bh
A=3(1/2bh)
well, the area is trippled
Hi! to solve the question, how many necklaces did anne make in 16 hours if she makes 10 items in 2 standard 8-hour work days, we should first check the time she needs to make each item.
3 individual hours to make a necklace, and 1 hour to make a ring. according to the problem, she made 10 items in 16 hours. this problem will most likely be trial and error. let’s try one first guess.
my first guess will be, maybe she will make 6 rings and 4 necklaces. 6 times 1 is 6, which takes 6 hours for the rings. 4 times 3 is equal to 12. 6 + 12 is too high! let’s try again.
what about 6 rings and 2 necklaces? 6 times 1 is 6, so that’s 6 hours. 2 times 3 is 6 hours! 6 plus 6 is 12, which is close, but not quite there!
let’s try 7 rings and 3 necklaces! 7 times 1 is 7 hours. 3 times 3 is equal to 9 hours! total that together, 7 plus 9, is equal to 16 hours spent!
so, the answer would be, “Anne made 7 rings and 3 necklaces within 16 hours.” hope this helped!:)
Answer:
A and D
Step-by-step explanation:
Negative times positive is always negative, thus making them less than 0. Negative times negative is positive, so B and C both have a positive product. Hope this helps
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.
