Answer:
she would run 6.4 miles in 48 min
Step-by-step explanation:
hope it helps
Essentially, what you are doing is taking each individual point and moving that point as specified.
So, for example, problem 1 has coordinates as follows: (be aware: I have terrible eyesight, so the points are being named based on what I think the letters are).
X: located at (2,0), move 1 unit left, new location: (1,0)
G: located at (4,0), move 1 unit left, new location: (3,0)
Q: located at (2,-2), move 1 unit left, new location: (1,-2)
C: located at (3,-4), move 1 unit left, new location: (2,-4)
Now, just plot the new shape.
Let me know if you need more help!
Answer:
2.5m
Step-by-step explanation:
50m divided by 20 = 2.5m
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
