Question

Integral pls i couldnt​

Answer 1

Simplify the integrand:

$\dfrac{4x^4 + 3x^2 + 5x}{x^2} = 4x^2 + 3 + \dfrac5x$

Now integrate one term at a time.

$\displaystyle \int 4x^2 \, dx = \frac43 x^3 + C$

$\displaystyle \int 3 \, dx = 3x + C$

$\displaystyle \int \frac5x \, dx = 5 \ln|x| + C$

Putting everything together,

$\displaystyle \int \frac{4x^4 + 3x^2 + 5x}{x^2} \, dx = \int \left(4x^2 + 3 + \frac5x\right) \, dx = \boxed{\frac43 x^3 + 3x + 5 \ln|x| + C}$