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3 years ago

I'll mark you the brainlest if you answer this correctly

Mathematics

2 answers:

NeX [460]3 years ago

8 0

Answer:

∠ A ≈ 24°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin A = $\frac{opposite}{hypotenuse}$ = $\frac{MR}{AR}$ = $\frac{6}{15}$ , thus

A = $sin^{-1}$ ( $\frac{6}{15}$ ) ≈ 24° ( to the nearest degree )

satela [25.4K]3 years ago

7 0

Answer:

A=14

Use formula A^2+B^2=C^2

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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

If f ( x ) f ( x ) is a linear function, f ( − 5 ) = 0 f ( - 5 ) = 0 , and f ( 2 ) = 4 f ( 2 ) = 4 , find an equation for f ( x

Effectus [21]

Answer:

f(x) = 4/7x + 20/7

Step-by-step explanation:

If we were to graph this function, we would see that the two points would be, (-5, 0), and (2, 4). First, we have to find the slope, which is equal to:

<u>(first y-coordinate - the second y coordinate)</u>

(first x-coordinate - second x coordinate)

= <u>(0 - 4)</u>

(-5 - 2)

= -4/-7 = 4/7. now, we multiple -5 by 4/7 and get -20/7. we have to add 20/7.

Thus, the answer is f(x) = 4/7x + 20/7

5 0

3 years ago

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Can someone complete the square??

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3 years ago

A man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast

Talja [164]

Answer:

4.41 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. We are asked to find how fast must he let out the string when the kite is flying on 34 ft. of string.

We will use Pythagoras theorem to solve for the length of side x as:

$x^2+16^2=34^2$