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Alik [6]
3 years ago
11

I'll mark you the brainlest if you answer this correctly​

Mathematics
2 answers:
NeX [460]3 years ago
8 0

Answer:

∠ A ≈ 24°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin A = \frac{opposite}{hypotenuse} = \frac{MR}{AR} = \frac{6}{15} , thus

A = sin^{-1} (\frac{6}{15} ) ≈ 24° ( to the nearest degree )

satela [25.4K]3 years ago
7 0

Answer:

A=14

Use formula A^2+B^2=C^2

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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)
maxonik [38]

Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

We have to find T,N and B at the given point t > (1,2/3,1)

r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k

B(1)=\frac{1}{3}

5 0
3 years ago
If f ( x ) f ( x ) is a linear function, f ( − 5 ) = 0 f ( - 5 ) = 0 , and f ( 2 ) = 4 f ( 2 ) = 4 , find an equation for f ( x
Effectus [21]

Answer:

f(x) = 4/7x + 20/7

Step-by-step explanation:

If we were to graph this function, we would see that the two points would be, (-5, 0), and (2, 4). First, we have to find the slope, which is equal to:

<u>(first y-coordinate - the second y coordinate)</u>

(first x-coordinate - second x coordinate)

= <u>(0 - 4)</u>

   (-5 - 2)

= -4/-7 = 4/7. now, we multiple -5 by 4/7 and get -20/7. we have to add 20/7.

Thus, the answer is f(x) = 4/7x + 20/7

5 0
3 years ago
Read 2 more answers
Can someone complete the square??
ira [324]

THE ANSWER IS..... X1= -6 & X2=0

5 0
3 years ago
A man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast
Talja [164]

Answer:

4.41 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. We are asked to find how fast must he let out the string when the kite is flying on 34 ft. of string.

We will use Pythagoras theorem to solve for the length of side x as:

x^2+16^2=34^2

x^2=34^2-16^2

x^2=900\\\\x=30

Now, we will use Pythagorean theorem to relate x and y because we know that the vertical side (16) is always constant.

x^2+16^2=y^2

Let us find derivative of our equation with respect to time (t) using power rule and chain rule as:

2x\cdot \frac{dx}{dt}+0=2y\cdot \frac{dy}{dt}

We have been given that \frac{dx}{dt}=5 , y=34 and x=30.

2(30)\cdot 5=2(34)\cdot \frac{dy}{dt}

300=68\cdot \frac{dy}{dt}

\frac{dy}{dt}=\frac{300}{68}

\frac{dy}{dt}=4.4117647058823529

\frac{dy}{dt}\approx 4.41

Therefore, the man must let out the string at a rate of 4.41 feet per second.

8 0
3 years ago
Is this correct if not what is it?
tia_tia [17]

if x = -1 and y= -3

y= 2x-1

-3=2(-1)-1

-3= -2-1

-3= -3

if x=0and y = -1

y=2x-1

-1=2(0)-1

-1=0-1

-1= -1

if x=1 and y=1

y=2x-1

1=2(1)-1

1=2-1

1=1

if x=2 and y=3

y=2x-1

3=2(2)-1

3=4-1

3=3

SO IT'S CORRECT ❤

THANJ YOU

8 0
3 years ago
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