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3 years ago

After being rearranged and simplified which equation cannot be solved using the quadratic formula?

Mathematics

2 answers:

sleet_krkn [62]3 years ago

8 0

Answer:

Step-by-step explanation:

5x^2 -3x+10 = 5x^2

Subtracting 5x^2 from each side

5x^2-5x^2 -3x+10 = 5x^2-5x^2

-3x+10 =0

We cannot use the quadratic formula since a =0

Marina86 [1]3 years ago

7 0

Answer:

Step-by-step explanation:

The answer is B because when you simplify it you get -3x + 10 = 0. Since this is no longer a quadratic equation, you can't solve it using the quadratic formula.

You might be interested in

Simplify: -6-3(5y+4)

Reil [10]

-6 - 3(5y + 4)
= - 6 - 15y -12
= -15y - 18

Hope it helped!

3 0

2 years ago

Read 2 more answers

Can someone help me with this? My teacher said its a must in the homework and i cant find a solution.

andrezito [222]

Answer:

$8x^3+28x^2-16x$

Step-by-step explanation:

Volume of rectangular prism: $l*b*h$ (l = length, b = breadth, h = height.)

Volume of rectangular prism:

$(x+4)*(2x-1)*4x$

$4x\left(x+4\right)\left(2x-1\right)$

Expand the two brackets using FOIL:

$4x(x* \:2x+x\left(-1\right)+4* \:2x+4\left(-1\right))$

$4x\left(2x^2+7x-4\right)$

Expand:

$4x* \:2x^2+4x* \:7x+4x\left(-4\right)$

$8x^3+28x^2-16x$

5 0

3 years ago

Which of the following order pairs is a solution of x+1/2y=1?<br><br> (-2,6)<br> (2,-6)<br> (-2,-6)

julsineya [31]

Y/2=1-x

y=2-2x

y(-2)=2-2(-2)=2+4=6, (-2,6)

So (-2, 6) is an ordered pair from x+y/2=1

3 0

2 years ago

Repost: Каков объем этой прямоугольной призмы?

torisob [31]

So first of all we should know that the <u>rectangular prism is a cuboid.</u>

$\\ \\$

<h3>Given :-</h3>

heigth = 9 in.
Length = 5 in.
Width = 4 in.

$\\$

Volume of cuboid.

$\\$

<h3>Solution:-</h3>

We know:-

$\bigstar \boxed{ \rm volume \: of \: cuboid = length \times width \times height}$

$\\ \\$

So:-

$\dashrightarrow \sf volume \: of \: cuboid = length \times width \times height \\$

$\\ \\$

$\dashrightarrow \sf volume \: of \: cuboid = 9 \times 5 \times 4 \\$

$\\ \\$

$\dashrightarrow \sf volume \: of \: cuboid = 45 \times 4 \\$

$\\ \\$

$\dashrightarrow \bf volume \: of \: cuboid = 180 {in}^{3} \\$

Therefore option C is correct .

$\\ \\$

$\\ \\$

$\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bigstar \: \bf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bigstar \: \bf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bigstar \: \bf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bigstar \: \bf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bigstar \: \bf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bigstar \: \bf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bigstar \: \bf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bigstar \: \bf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bigstar \: \bf{Volume_{(cuboid)} = lbh}\\ \\ \bigstar \: \bf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bigstar \: \bf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

6 0

2 years ago

PLS answer ASAP TY!!

Nastasia [14]

The scale factor is 2

3 0

3 years ago