Answer:
The numerical value of the trigonometric function is 30 °
Step-by-step explanation:
Given trigonometric function as :
+
= 4
or, Taking LCM we get
= 4
Or, ( 1 + cos x )² + sin² x = 4 × ( sin x ) × ( 1 + cos x )
1 + cos² x + 2 cox + sin² x = 4 sin x + 4 sin x × cos x
or, ( cos² x + sin² x ) + ( 1 + 2 cos x ) = 4 sin x ( 1 + cos x )
∵ cos² x + sin² x = 1
or, 1 + 1 + 2 cos x = 4 sin x ( 1 + cos x )
or, 2 + 2 cos x = 4 sin x ( 1 + cos x )
or, 2 ( 1 + cos x ) = 4 sin x ( 1 + cos x )
Or,
= sin x
Or, sin x = 
∴ x = 
∵ sin 30 ° = 
I.e x = 30 °
Hence The numerical value of the trigonometric function is 30 ° answer
Answer:
gcd(20a,14b)
Step-by-step explanation:
add 7a and 3a, and add 5b to 2b,
you're left with 10a + 7b, times two to both, and you have
20a + 14b
so the answer is gcd(20a,14b)
i have no clue i haven't done this before so thats what i'm guessing happens? good luck :,)
Answer:
115 in²
Step-by-step explanation:
SA = Area of triangular surfaces + area of the square base
SA= 2bh + b²
SA = 2(5)(9)+5²
SA = 90+25
SA = 115