Question

Solve for x in the equation x² + 2x + 1 = 17

Answer 1

Answer:

The solution of x are  $x=-1+\sqrt{17}$ and  $x=-1-\sqrt{17}$

Step-by-step explanation:

We are given $x^2+2x+1=17$

We need to solve for x.

First we move 16 to left side ans then factor it

$x^2+2x+1-17=0$

$x^2+2x-16=0$

Using quadratic formula,

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-2\pm\sqrt{4+64}}{2}$

$x=\dfrac{-2\pm2\sqrt{17}}{2}$

$x=-1\pm\sqrt{17}$

Thus, The solution of x are  $x=-1+\sqrt{17}$ and  $x=-1-\sqrt{17}$