All categories

3 years ago

1. You have two playing cards with a sum of (−12) in your hand.

Mathematics

1 answer:

Verdich [7]3 years ago

3 0

Yes the person is right I was trying to type it but they beat me to it

You might be interested in

Sam ran 2

daser333 [38]

In total he ran 19 miles based off of how the question looks. It looks like I needed to add each number up.

5 0

2 years ago

A random sample of 8 recent college graduates found that starting salaries for architects in New York City had a mean of $42,653

ycow [4]

Answer:

C. (36337.32, 48968.68)

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{9114}{\sqrt{8}} = 6315.68$

The lower end of the interval is the sample mean subtracted by M. So it is 42653 - 6315.68 = 36337.32.

The upper end of the interval is the sample mean added to M. So it is 42653 + 6315.68 = 48968.68.

So the correct answer is:

C. (36337.32, 48968.68)

3 0

3 years ago

1. 7+8-2 .

AnnZ [28]

Answer:

1. 13

2. 11

3. 10

4. 9

5. 12

6. 16

7. 14

8. 40

Step-by-step explanation:

8 0

3 years ago

Ultiple Choice

gulaghasi [49]

Answer:

4 12

3 18

5 20

7 42

5 15

Step-by-step explanation:

all of the above form a proportion

8 0

3 years ago

An observer for a radar station is located at the origin of a coordinate system. Find the bearing of an airplane located at the

AfilCa [17]

Answer:

135 degrees

$S45^{0}E$

Step-by-step explanation

Consider the attached diagram

we are required to find the bearing of the aeroplane,

Consider the right angled triangle BOE

|OB|=4 unit

|AB|=4 Units

$Tan \alpha =\frac{Opposite}{Adjacent} =\frac{4}{4} \\\\\alpha=Tan^{-1} 1=45 degrees$

The Bearing of the Aeroplane is therefore given:

(i)From North Clockwise as: 90+45 =135 degrees

(ii)From a North South Line as $S45^{0}E$

6 0

3 years ago