Answer:
The average rate of change over the interval is 120
Step-by-step explanation:
For a function f(x) the average rate of change over an interval [a,b] is given as;
f(b)-f(a)/b-a
in this case, a is 2 and b is 4
f(b) is 256 and f(a) is 16
Substituting these values in the equation for rate of change, we have;
(256-16)/(4-2) = 240/2 = 120
We are given the points
<span>(0,-4),(1,0),(2,2)
The standard form a quadratic function (in terms of x) is
y = Ax2 + Bx + C
Subsitute the points
-4 = 0 + 0 + C
C = -4
0 = A + B - 4
2 = 4A + 2B - 4
Solve for A and B
A = -1
B = 5
The function is
y = -x2 + 5x - 4</span>
Substituting y=6x+2 into equation 3y - 18x =12 looks like:
3(6x + 2) - 18x = 12
18x + 6 - 18x = 12 distributive property left side
6 = 12 simplifying the left side
We now see a contradiction: 6 does not equal 12 What this tells us is that there is no solutions to this equation. So choice 'C' ...
Answer:
11.2
Step-by-step explanation:
divide 160 by 14.3
Answer:
Step-by-step explanation:
Given equation:
Cube root both sides:
![\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7Bp%5E3%7D%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\implies p= \sqrt[3]{\dfrac{1}{8}}](https://tex.z-dn.net/?f=%5Cimplies%20p%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D)
![\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:](https://tex.z-dn.net/?f=%5Ctextsf%7BApply%20exponent%20rule%7D%20%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3A)
Rewrite 8 as 2³:
Simplify:
