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professor190 [17]
4 years ago
12

HELP PICTURE IS SHOWN

Mathematics
1 answer:
n200080 [17]4 years ago
4 0
Ok so form what i can see i belive but not shure that it is positive 7
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What is the average rate of change for this exponential function for the interval from x = 2 to x = 4?
Hunter-Best [27]

Answer:

The average rate of change over the interval is 120

Step-by-step explanation:

For a function f(x) the average rate of change over an interval [a,b] is given as;

f(b)-f(a)/b-a

in this case, a is 2 and b is 4

f(b) is 256 and f(a) is 16

Substituting these values in the equation for rate of change, we have;

(256-16)/(4-2) = 240/2 = 120

8 0
3 years ago
(0,-4),(1,0),(2,2) find a quadratic function in standard form for each set of points.
Sphinxa [80]
We are given the points
 <span>(0,-4),(1,0),(2,2)
The standard form a quadratic function (in terms of x) is
y = Ax2 + Bx + C
Subsitute the points
-4 = 0 + 0 + C
C = -4

0 = A + B - 4

2 = 4A + 2B - 4

Solve for A and B
A = -1
B = 5

The function is
y = -x2 + 5x - 4</span>
4 0
3 years ago
What is the solution of the system? Use substitution.
nekit [7.7K]
Substituting y=6x+2 into equation 3y - 18x =12 looks like:

3(6x + 2) - 18x = 12
18x + 6 - 18x = 12  distributive property left side
6 = 12  simplifying the left side

We now see a contradiction:   6 does not equal 12  What this tells us is that there is no solutions to this equation.  So choice 'C' ...
8 0
3 years ago
Read 2 more answers
Solve this linear equation for p.
Fynjy0 [20]

Answer:

11.2

Step-by-step explanation:

divide 160 by 14.3

6 0
3 years ago
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P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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