Question

A hollow shaft has a cross-sectional area 125.6cm2 and a bore of 8cm in diameter. Calculate the outer diameter of the shaft to 2s.f. With the explanations please

Answer 1

Answer:

The outer diameter of the shaft to 2s.f is  12.65cm

Step-by-step explanation:

We know that the expression for the area of a circular cross section is

A= $\frac{\pi d^2}{4}$

given data

area of cross section= $125.6cm^2$

bore diameter d= 8cm

from the area of cross section we can solve for the outer diameter D

$Area of cross section=\frac{\pi D^2}{4} \\\\125.6= \frac{3.142*D^2}{4}$

solving for D we have

$3.142*D^2= 125.6*4\\\3.142*D^2= 502.4\\D^2= \frac{502.4}{3.142} \\D^2= 159.8981\\D=\sqrt{159.8981} \\D= 12.6450\\D= 12.65cm$