Given the following absolute value function find the range. ƒ(x) = |x + 5| - 8

1 answer:

7 0

The result of an absolute value operation is never negative. So the smallest that the expression |x+5| can be is 0.

Tacking on "-8" to |x+5| leads to |x+5|-8

The range of this is [-8, infinity) since the smallest |x+5|-8 can be is -8. All I did was subtract 8 from the smallest value of |x+5|

Final Answer: choice C)

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