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Juli2301 [7.4K]
3 years ago
14

Given the following absolute value function find the range. ƒ(x) = |x + 5| - 8

Mathematics
1 answer:
balandron [24]3 years ago
7 0
The result of an absolute value operation is never negative. So the smallest that the expression |x+5| can be is 0. 

Tacking on "-8" to |x+5| leads to |x+5|-8

The range of this is [-8, infinity) since the smallest |x+5|-8 can be is -8. All I did was subtract 8 from the smallest value of |x+5|

Final Answer: choice C)
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8 0
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(negative 5x squared) to the third power
BARSIC [14]

(-5x^2)^3 =

= (-5)^3(x^2)^3

= -125x^{2 \times 3}

= -125x^6

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D and E

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