<span><span>1. </span></span>Draw a line segment of length s. Label its endpoints PPP and QQQ.<span><span>
</span><span>2. </span></span>Extend the line segment past QQQ.<span><span>
</span><span>3. </span></span>Erect the perpendicular to PQ−→−normal-→PQ {PQ} at QQQ
<span><span>4. </span></span>Using the line drawn in the previous step, mark off a line segment of length sss such that one of its endpoints is QQQ. Label the other endpoint as RRR.<span><span>
</span><span>5. </span></span>Draw an arc of the circle with center PPP and radius PQ normal PQ\ {PQ}.<span><span>
</span><span>6. </span></span>Draw an arc of the circle with center RRR and radius QR normal QR\overline{QR} to find the point SSS where itintersects the arc from the previous step such that S≠QSQS\neq Q.<span><span>
</span><span>7. </span></span>Draw the square PQRSPQRSPQRS.
<span>Following option is correct answer
Shape 1 is not congruent to shape 2 because a sequence of rigid transformations will not map shape 1 onto shape 2.</span>
Now cos⁻¹(0.7) is about 45.6°, that's on the first quadrant.
keep in mind that the inverse cosine function has a range of [0, 180°], so any angles it will spit out, will be on either the I quadrant where cosine is positive or the II quadrant, where cosine is negative.
however, 45.6° has a twin, she's at the IV quadrant, where cosine is also positive, and that'd be 360° - 45.6°, or 314.4°.
now, those are the first two, but we have been only working on the [0, 360°] range.... but we can simply go around the circle many times over up to 720° or 72000000000° if we so wish, so let's go just one more time around the circle to find the other fellows.
360° + 45.6° is a full circle and 45.6° more, that will give us the other angle, also in the first quadrant, but after a full cycle, at 405.6°.
then to find her twin on the IV quadrant, we simply keep on going, and that'd be at 360° + 360° - 45.6°, 674.4°.
and you can keep on going around the circle, but only four are needed this time only.
It is now 11:50 p.m. because the clock goes back to a.m. when it hits 12
Answer:
Vegetable soup costs less because it's only $0.24/oz while chicken soup costs $0.25/oz.
Step-by-step explanation:
Vegetable = $2.88/12 = $0.24/per 1 oz
Chicken = $2.25/9 = $0.25/per 1 oz
