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3 years ago

Solve for b: y = mx + b +mx + mx y + mx = b

Mathematics

2 answers:

Mekhanik [1.2K]3 years ago

7 0

Answer:

b=−3mx+y.

Step-by-step explanation:

Kruka [31]3 years ago

4 0

Answer:

Here's what I got. First of all, did you meant y=mx+b+mx+mxy+mx=b, because that's undefined, or did you meant y=mx+b+mx+mx, which is b=−3mx+y.

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Which property is used 2(x+4)=2x+8

Elenna [48]

Answer:

Apply the distributive property

2x+2(4)=2x+8

Multiply 2 by 4

2x+8=2x+8

Move all terms containing x to the left and subtract 2x

2x+8-2x=8

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2x+8-2x

Subtract 2x from 2x

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Step-by-step explanation:

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3 years ago

a square painting has an area of 81x^2-90x-25. A second square painting has an area of 25x^2+30x+9. What is an expression that r

galina1969 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ----> the area of the second square painting

D -----> the difference of the areas

we have

$A1=81x^{2}-90x-25$

$A2=25x^{2}+30x+9$

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

$D=(25x^{2}+30x+9)-(81x^{2}-90x-25)$

$D=(-56x^{2}+120x+34)$

case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

$D=(81x^{2}-90x-25)-(25x^{2}+30x+9)$

$D=(56x^{2}-120x-34)$

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4 years ago

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3 years ago

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DedPeter [7]

Answer:

The answer is A: y^2/2x

Step-by-step explanation:

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3 years ago