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Natalka [10]
3 years ago
11

Write an equation for each linear function described. Show your work. The graph of the function passes through the point (2,1),

and y increases by 4 when x increases by 1.
Mathematics
1 answer:
svp [43]3 years ago
8 0

Step-by-step explanation:

As

  • The graph of the function passes through the point (2,1), and
  • y increases by 4 when x increases by 1.

so

x             y

2             1

3             5

4             9

5             13

6             17

and so on

From the table:

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(2,\:1\right),\:\left(x_2,\:y_2\right)=\left(3,\:5\right)

m=\frac{5-1}{3-2}

m=4

As the slope-intercept form of the line is

y=mx+b

putting m=4 and any point, let say (2, 1) to find y-intercept 'b'.

1=\left(4\right)2+b

8+b=1

8+b-8=1-8

b=-7

So putting b=-7 and m=4  in the slope-intercept form of the line

y=\left(4\right)x+\left(-7\right)

y=4x-7

Therefore, the equation for the linear function will be:

y=4x-7

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A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
2.5kg of apples cost £3.60 work out the cost of 3.5kg of apples
professor190 [17]

Answer:

£5.04

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Let's first find the unit cost.

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To find out how much money 3.5kg of apples costs, we simply need to multiply the unit price by 3.5.

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Answer:

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