Answer:
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
4( x + 1.5)^2 + 0
Discussion:
4x^2 + 12x + 9 = => factor "4" from first 2 terms
4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2
4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =
4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25
4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9
4 ( x+ 1.5)^2 + 0
Thank you,
MrB
There must be a mistake in your question:
If 3 x ≤ 9, then : x ≤ 3 and :
x + 4 > 2
x > 2 - 4
x > - 2
Answer: D)
Solution set : - 2 < x ≤ 3
Y^2 -11y = 0
We can factor it:
y * (y -11) = 0
So y = 11, 0
The writing isnt so clear to me
