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4 years ago

What is the constant of proportionality in the equation x/y=2/9 HURRY

Mathematics

1 answer:

const2013 [10]4 years ago

5 0

Answer:

1/9

Step-by-step explanation:

Separate the fraction (1/9) from the variable x:

y = (1/9)x.

1/9 is the constant of proportionality.

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What is the LCM of 9 and 15?

Charra [1.4K]

Answer:

Step-by-step explanation:

15+15=30

30/9=3 r3 doesn't work

30+15=45

45/9=5

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3 years ago

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Solve for x <br> y=-1/2x=3

ANEK [815]

Answer:

-6

Step-by-step explanation:

x=-6

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3 years ago

If the estimate of expected population proportion having a desired characteristic based on intuition is 60 percent and the accep

Anika [276]

Answer:

Step-by-step explanation:

Our values are:

N = 100,000 (We assume it)

Proportion is p = 0.6

Margin of error (E) = 0.05

confidence-level (cl) = 0.95

Z-value = 1.96

We need to approach through Proportion,

$n=\frac{ (z_2 * p *q) + ME_2}{ME_2 + z_2 * p * q / N}$

Substituting,

$n = \frac{(1.962*0.6*0.4)+0.052}{0.052 + \frac{1.962 * 0.6 * 0.4}{100000}}$

$n= \frac{(3.841 * 0.24)+0.0025}{0.0025+\frac{3.841*0.24}{100000}}$

$n =\frac{ 0.9243}{0.002509}$

$n= 368$

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3 years ago

Which two expressions are equivalent?

blsea [12.9K]

Answer:

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. Ding A single lap should be completed each time you hear this sound. Ding Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over. The test will begin on the word start. On your mark, get ready, ding

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.

Ratling [72]

Answer:

1)Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

2) Two critical values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) $z=-2.40$

4) $p_v =2*P(z$

5) Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

$\bar X_{men}=23$ represent the mean for the sample men

$\bar X_{women}=28$ represent the mean for the sample women

$\sigma_{men}=5$ represent the population standard deviation for the sample men

$\sigma_{women}=10$ represent the population standard deviation for the sample women

$n_{men}=25$ sample size for the group men

$n_{women}=30$ sample size for the group women

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

1）Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2）Determine the critical value(s).

Based on the significance level $\alpha=0.01$ and $\alpha/2=0.005$ we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40$

4）What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

$p_v =2*P(z$

5）Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

4 0

3 years ago