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sammy [17]
3 years ago
10

2.5.3 Journal: Proofs of Congruence

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0
I am doing this on apex aswell and i am stuck for the last few ones. I know that the answer to #1 is: Natalie- SAS and Emma- SSS the other ones im not so sure about. sorry for the lack of help, just thought one answer is better than none lol
tayo
3 years ago
do you have question 5
MakcuM [25]3 years ago
8 0

Statement Reason

AB and BC are congruent

CPCTC

DB and FB are congruent

CPCTC

Angle EBD congruent to angle EFB

CPCTC

Angle ABD congruent to angle EBD

Alternate angle theorem

Angle FBC congruent to angle EFB

Alternate angle theorem

ABD CBF

SAS theorem


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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Minchanka [31]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the distance traveled by deluxe tire .

As per given , we have

Null hypothesis : H_0 : \mu \geq50000

Alternative hypothesis : H_a : \mu

Since H_a is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.

Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

s=sample standard deviation

For n= 31,\ \sigma=8000,\ \overline{x}=46,800\ \&\ s=46,800, we have

z=\dfrac{46800-50000}{\dfrac{8000}{\sqrt{31}}}=-2.23

By using z-value table,

P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23)   [∵P(Z≤-z)=1-P(Z≤z)]

=1-0.9871=0.0129

 Decision : Since p value (0.0129) < significance level  (0.05), so we reject the null hypothesis .

[We reject the null hypothesis when p-value is less than the significance level .]

Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.

4 0
3 years ago
A certain math teachers likes to keep a box of prizes to distribute to students. The math teacher likes to keep at least twice a
Law Incorporation [45]

Option C

Math teacher would need to buy 130 prizes

<em><u>Solution:</u></em>

Given that,

Math teacher currently has 109 students and the box has 88 prizes in it

The math teacher likes to keep at least twice as many prizes in the box as she has students

So, she wants the number of prizes to be twice the number of students

Therefore,

number of prizes = 2 x 109 students

number of prizes = 2 x 109 = 218 prizes

The box has 88 prizes in it

Therefore, number of prizes she would need to buy is:

⇒ 218 - 88 = 130

Thus she would need to buy 130 prizes

3 0
3 years ago
If f(x)=3x+1 then f(a+h)-f(a)
Varvara68 [4.7K]
F(x) = 3x+1
put x = a+h
f(a+h)  = 3(a+h) + 1
f(a+h) = 3a + 3h + 1
put x = a
f(a) = 3a + 1
f(a+h)-f(a) = 3a + 3h + 1 -(3a+1)
f(a+h)-f(a) = 3a +3h + 1 - 3a -1
f(a+h)-f(a) = 3h
7 0
3 years ago
The midpoint of (2,7) and (6,3)
White raven [17]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP!!! Show your work too, please!
dimulka [17.4K]

Step-by-step explanation:

first fish tank: 95-4x

second fish tank: 40+5x

1. Define variable

The variable x represents the number of days.

2. Write the inequality

<em>95-4x=40+5x</em>

<em />

3. You probably don't need the answer but I am just going to solve.

The first fish tank will have less water than the second fish tank after 7 days.

<em>95-4x=40+5x </em>

<em>95-4(7)=40+5(7)</em>

<em>95-28=40+35</em>

<em>67=75</em>

<em>Since the first equation (95-4x) represents the first fish tank, and the second equation (40+5x) represents the second fish tank, the solution shows how the amount of water in the first fish tank is less than the amount of water un the second fish tank after 7 days.</em>

8 0
3 years ago
Read 2 more answers
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