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sammy [17]
3 years ago
10

2.5.3 Journal: Proofs of Congruence

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0
I am doing this on apex aswell and i am stuck for the last few ones. I know that the answer to #1 is: Natalie- SAS and Emma- SSS the other ones im not so sure about. sorry for the lack of help, just thought one answer is better than none lol
tayo
2 years ago
do you have question 5
MakcuM [25]3 years ago
8 0

Statement Reason

AB and BC are congruent

CPCTC

DB and FB are congruent

CPCTC

Angle EBD congruent to angle EFB

CPCTC

Angle ABD congruent to angle EBD

Alternate angle theorem

Angle FBC congruent to angle EFB

Alternate angle theorem

ABD CBF

SAS theorem


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NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

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