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Vika [28.1K]
4 years ago
12

A pair of dice is rolled. What is the probability that the sum of the two dice will be greater than 8 given that the first die r

olled is a 5?
Mathematics
2 answers:
KatRina [158]4 years ago
8 0

Answer:

1/2

Step-by-step explanation:

First die rolled 5

Second die can roll 1, 2, 3, 4, 5, 6

Only if the second die rolls 4, 5, 6 will the sum be greater than 8.

p(sum > 8) = 3/6 = 1/2

xenn [34]4 years ago
4 0

Answer: 1/2

Step-by-step explanation:

First die rolled 5

Second die can roll 1, 2, 3, 4, 5, 6

Only if the second die rolls 4, 5, 6 will the sum be greater than 8.

p(sum > 8) = 3/6 = 1/2

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The ratio of boys to girls in a class is 2:3. there are twelve boys in the class. how many girls are there
gogolik [260]
The answer is 18

Solution: 2:3 2x6=12
3x6=18
Hope this help
4 0
3 years ago
How fast is the train going if it can travel<br> 100 miles in 30 minutes?
DerKrebs [107]

30 min = 30/60 hr = 0.5 hr

d = rt

100 = r*0.5

100/0.5 = r

200 = r

r = 200 mph.

We know that Rate = distance/time

(30 minutes is .5 hour)

Rate=100 mile/.5 hour

Divide and we get:

Rate=200 MPH

(Hint: MPH is Miles per Hour---Per means "for each")

Make sense?

4 0
2 years ago
!!50 point!!!
SSSSS [86.1K]

Answer:

  • B: the area of the triangle GHK plus the area of triangle HIK

Step-by-step explanation:

<u>Connect points H and K and you have two triangles:</u>

  • ΔGHK and ΔHIK

<u>The answer options:</u>

statement A:

  • the area of triangle GHL plus the area of triangle HIJ
  • <u>False</u>. This leaves a gap (HJKL)

statement B:

  • the area of the triangle GHK plus the area of triangle HIK
  • <u>True</u>

statement C:

  • the area of the triangle GJK plus the area of triangle ILK
  • <u>False</u>. This leaves a gap and overlap.

statement D:

  • the area of triangle GHK plus the area of triangle ILK ​
  • <u>False</u>. This leaves a gap and overlap.

7 0
3 years ago
The equation d = can be used to calculate the density, d, of an object with mass, m, and volume, V. Which is an equivalent equat
gulaghasi [49]
D=m/v
dv=m
v=m/d
..........
5 0
4 years ago
Read 2 more answers
Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t
Yanka [14]

Answer:

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

\hat p=\frac{X}{n} estimated proportion of  scissors selected for each friend

p_o=\frac{1}{3}=0.333 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:  

Null hypothesis:p\geq 0.333  

Alternative hypothesis:p < 0.333  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

6 0
4 years ago
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