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2 years ago

Does anyone want to be my fortnite girlfreind

Mathematics

2 answers:

Cloud [144]2 years ago

7 0

STAN AND STREAM VICTON ATEEZ AND TXT NOW

natima [27]2 years ago

5 0

Answer:

Step-by-step explanation:

trust me this is probbly the brainiests answer. >﹏<

B---8

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Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

Question 6 options: tan D tan F cos F sin F

ivanzaharov [21]

Answer:

tan F

Step-by-step explanation:

tangent is opposite/adjacent

the opposite side of F is 8 and the adjacent is 15

8/15 is therfore = tan F

7 0

2 years ago

Read 2 more answers

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

Effectus [21]

Answer:

make x→0

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→ $p(0)=2$

$------$

Replace x→-1

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

Now make x→2

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!

5 0

2 years ago

Which point would be the image of (-3,-9) after a reflection over the y-axis?

Lera25 [3.4K]

It would be b (-3,9)

6 0

2 years ago

Read 2 more answers

Evaluate the function.

wolverine [178]

Answer:

-87

Step-by-step explanation:

-(-7^2) + 6(-7) + 4

-49 -42 + 4

-87

7 0

2 years ago

Read 2 more answers