All categories

2 years ago

Calculate the volume of the following object:

Mathematics

2 answers:

Paraphin [41]2 years ago

7 0

Answer:

5*5*5=125

volume of cylinder=137.44

137.44+125=262.44

Step-by-step explanation:

frozen [14]2 years ago

3 0

Answer:

262.44 cubic metres.

Step-by-step explanation:

First, we can calculate the volume of the cylinder by doing pi * r^2 * h. In this case, r is 5 / 2 and h is 7.

pi * (5/2)^2 * 7 = pi * 25/4 * 7 = pi * 6.25 * 7 = pi * 43.75 = 3.14159265 * 43.75 = 137.4446784 cubic m.

Seconds, we calculate the volume of the cube. It is 5^3 = 5 * 5 * 5 = 25 * 5 = 125 cubic m.

137.4446784 + 125 = 262.4446784, which is about 262.44 cubic metres.

Hope this helps!

You might be interested in

How can you do subtract three Digit numbers

Aleonysh [2.5K]

First off, you have to subtract the 3rd number, then carry the number if so, then do the same to the second and first number, did i help in any way?

4 0

3 years ago

Read 2 more answers

The product of two numbers is 48, and one of the numbers is 12. Find the other number.

Anuta_ua [19.1K]

Two numbers, one being 12, are multiplied to equal 48.

Therefore, the answer is B) 12x = 48

7 0

2 years ago

Read 2 more answers

Match each quadratic equation with its solution set.

Luba_88 [7]

Answer:

2x²-32 ⇒ x²=16⇒ (-4,4)

4x²-100 ⇒x²=25 ⇒(-5,5)

x²-55=9 ⇒x²=64 ⇒(-8,8)

x²-140=-19 ⇒x²=121 ⇒(-11,11)

2x²-18=0 ⇒x²=9 ⇒(-3,3)

5 0

3 years ago

Read 2 more answers

For Number 6 and 7 It says You rewrite the expression this time

GarryVolchara [31]

We can't help unless we know what to "rewrite"

7 0

2 years ago

The mean student loan debt for college graduates in Illinois is $30000 with a standard deviation of $9000. Suppose a random samp

Nataly [62]

Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

$P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)$

$P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}} )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}} )$

$P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}} )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}} )$

$P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})$

$P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})$

From Z tables:

$P(31000 < X$

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0

2 years ago