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mihalych1998 [28]
3 years ago
9

Based on this information, which pair of lines, together, could be perpendicular to RS? Select two options.

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer: EA & FG

Step-by-step explanation:

kupik [55]3 years ago
4 0

Answer:

EA

FG

EAStep-by-step explanation:

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4. Use the diagram below to answer the question
ludmilkaskok [199]

Answer:

≈ 397 m

Step-by-step explanation:

Using Pythagoras' identity on the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

Let h represent the height of the balloon above ground, then

h² + 50² = 400², that is

h² + 2500 = 160000 ( subtract 2500 from both sides )

h² = 157500 ( take the square root of both sides )

h ≈ 397 m ( to the nearest metre )

4 0
3 years ago
True or False, If you double one of the dimensions of a rectangular prism, the surface area will double.
ollegr [7]
False.
Because there are three dimensions, not just two dimensions, so two of the sides will not be affected by the changing of one of the dimensions.
3 0
4 years ago
A zoo is building a new large-cat exhibit. Part of the space will be used for lions and part for leopards. The exhibit will have
Fittoniya [83]

The equations for the expenses for maintaining 4 lions and 4 leopards in the new large-cat exhibit are as follows:

                             Lions                  Leopard

Equations       4x = 32,000         4y = 24,000

<h3>What is an equation?</h3>

An equation is a mathematical statement that shows the values of two mathematical expressions are equal.

An equation is made up of two mathematical expressions connected by an equal sign.

<h3>Data and Calculations:</h3>

Annual expenses for lion per unit, x = $8,000

Annual expenses for leopard per unit, y = $6,000

Total number of larget-cats required = 8

Let the cost of maintaining 4 lions = 4x

Let the cost of maintaining 4 leopards = 4y

Total cost for 4 lions = $32,000 (8,000 x 4)

Total cost for 4 leopards = $24,000 (6,000 x 4)

Total cost for eight large cats per year = $56,000 ($32,000 + $24,000)

Equation for lions, 4x = 32,000

Equation for leopards, 4y = 24,000

The total costs for maintaining eight large cats in all will be <u>$56,000</u> per year.

Thus, the equations for the expenses for maintaining 4 lions and 4 leopards in the new large-cat exhibit are <u>4x = 32,000</u> and <u>4y = 24,000</u>, respectively.

Learn more about equations at brainly.com/question/13763238

#SPJ1

5 0
2 years ago
Graph it y=1/2x+8\\5x+2y=-8[/tex]
SSSSS [86.1K]

Answer: ITS IS THIS or that i dont know what you mean.

Step-by-step explanation: Is this what you're looking for? if you were paying attention you would've KNOWN SO NExt time PAY ATTENTION BUT GOOD LUCK

8 0
2 years ago
Read 2 more answers
Josh is going to the store to buy cakes to share with the fifth grade. He wants to share the cakes with 86 students. He buys 35
Ipatiy [6.2K]

Answer:

Everyone will get \frac{35}{86} amount of cakes.

Step-by-step explanation:

Given:

Number of Cakes Josh buys = 35

Number of Students Josh wants to share = 86

Josh need to share cakes with fifth grade students.

We need to find the fraction of cakes everyone will get.

So to find the the fraction of cakes everyone will get can be calculated by dividing Number of Cakes Josh buys with Number of students he want to share with.

Amount of cakes Every one will get = \frac{\textrm{Number of Cakes}}{\textrm{Number of Students}}

Now Substituting the values we get;

Amount of cakes Every one will get = \frac{35}{86}

Hence Everyone will get \frac{35}{86} amount of cakes.

7 0
3 years ago
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