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Crank
3 years ago
15

Make r the subject.Q=4πr^2+1/3πr^2h​

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

r =  \sqrt{\frac{3Q}{\pi(12 + h)}}

Step-by-step explanation:

Q = 4\pi {r}^{2}  +  \frac{1}{3} \pi {r}^{2} h \\  \\ Q = {r}^{2} \bigg(4\pi   +  \frac{1}{3} \pi  h  \bigg)\\  \\ Q = {r}^{2} \pi\bigg( \frac{12}{3}    +  \frac{1}{3}   h  \bigg)\\  \\ Q = {r}^{2} \pi\bigg( \frac{12 + h}{3}   \bigg)\\  \\ {r}^{2} =  \frac{Q}{\pi\bigg( \frac{12 + h}{3}   \bigg)}  \\  \\ {r}^{2} =  \frac{3Q}{\pi(12 + h)}  \\  \\ r =  \sqrt{\frac{3Q}{\pi(12 + h)}}

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Add +1 in both sides to complete the expression such as:
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3 years ago
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