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3 years ago

What is the value of i5 1 −i i −1

1 answer:

8 0

I’m assuming you mean: What is the value of i^5? This symbol (^) means that the 5 is an exponent of five.
If you did mean i^5, then the answer is i.

or to put it in simpler terms,
i^5=i

I hope this helped!

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Write the inequality to represent the situation: "x can be no more than 5." Copy/paste the symbols if you need to: < > ≤ ≥

Dmitrij [34]

Answer:

I think it would be ≤

Step-by-step explanation:

I think it may be that because it claimed to say "Can be no more than 5".

So that means it can be equal and less than 5. But no more than five.

The sign i choose means Can be equal or less than.

Hope this helps! <3

3 0

3 years ago

Brainliest if correct Question

kozerog [31]

Answer:

x=2

Step-by-step explanation:

18−7x=2x

Step 1: Simplif

18−7x=2x

18+−7x=2x

−7x+18=2x

Step 2: Subtract 2x from both sides.

−7x+18−2x=2x−2x

−9x+18=0

Step 3: Subtract 18 from both sides.

−9x+18−18=0−18

−9x=−18

Step 4: Divide both sides by -9.

4 0

2 years ago

Read 2 more answers

The value of two numbers if their sum is 21 and their difference is 3

iragen [17]

Answer:

9 and 12

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$