Answer:
Her regular weekly pay is $62 and her annual salary is $3100.
Step-by-step explanation:
Given that her hourly wage=$15.50 / hour
As she works 40 hours per week, so her weekly pay = 15.50 x 40 = $62/ week.
If she works 50 weeks each year, so her yearly pay = 62x50=$3100 /year.
Hence, her regular weekly pay is $62 and her annual salary is $3100.
Answer:
x≤-3 1/2 or x>1
Step-by-step explanation:
The way we solve this is we simply rearrange the equation using algebra.
Step 1) For the first inequality, subtract 1/2 from both sides. This gets x by itself and turns the RHS into -3 1/2.
Step 2) For the second, add 3 to both sides. Once again, x is by itself, and the RHS is equal to 1.
Answer:
Jaime = 11
Sammy = 44
Step-by-step explanation:
It is given that Sammy is eleven less than five times Jaime's age. Use parameter (S) to represent Sammy's age, and parameter (J) to represent Jaime's age. Form an equation based on this given information:
S = 5J - 11
It is given that the sum of the two girl's ages is (55), use an equation to represent this.
S + J = 55
Substitute in the expression for the value of (S) in terms of (J),
(5J - 11) + J = 55
Simplify,
6J - 11 = 55
Inverse operations,
6J - 11 = 55
6J = 66
J = 11
Backsolve for the value of (S), substitute in the value of (J) into the equation for (S) and solve,
S = 5(J) - 11
S = 5(11) -11
S = 55 - 11
S = 44
Answer:
x = 4
Explanation:
For the right hand side:
log base 9 of 8 + log base 9 of (x-2) = log base 9 (8*(x-2))
= log base 9 of (8x-16)
For the left hand side:
2*log base 9 of x = log base 9 of x^2
Now, equating the two sides and solving for x:
log base 9 of (8x-16) = log base 9 of x^2
This means that:
x^2 = 8x - 16
x^2 - 8x + 16 = 0
(x-4)^2 = 0
Therefore:
x = 4
Hope this helps :)
