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artcher [175]
4 years ago
13

two bags contains 10 balls each. Every round you choose with equal probability one of the two bags and pick out a ball. After a

while, you choose an empty ball. What is the probability for the other bag to contain exactly 4 balls at that time?
Mathematics
1 answer:
Stells [14]4 years ago
4 0

Answer:

6.10%

Step-by-step explanation:

For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2

Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)

Now on the 17th trial, an empty bag is chosen

Therefore the required probability will be;

16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%

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Answer:

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Step-by-step explanation:

We want to simplify:

-5-\sqrt{-44}

We rewrite the expression under the radical sign to obtain:

-5-\sqrt{4\times11\times -1}

We split the expression under the radical sign to get:

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Recall that:

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This implies that:

-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}=-5-2\sqrt{11}i

Therefore -5-\sqrt{-44}=-5-2\sqrt{11}i

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Keith_Richards [23]

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This is the slope of the tangent line to the function at (-1, 4).

Use the point-slope formula to get the equation for the tangent line:

<em>y</em> - 4 = 4 (<em>x</em> - (-1))   →   <em>y</em> = 4<em>x</em> + 8

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