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artcher [175]
4 years ago
13

two bags contains 10 balls each. Every round you choose with equal probability one of the two bags and pick out a ball. After a

while, you choose an empty ball. What is the probability for the other bag to contain exactly 4 balls at that time?
Mathematics
1 answer:
Stells [14]4 years ago
4 0

Answer:

6.10%

Step-by-step explanation:

For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2

Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)

Now on the 17th trial, an empty bag is chosen

Therefore the required probability will be;

16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%

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DedPeter [7]

Answer:

w = 32

Step-by-step explanation:

Remark

The value of the exterior angle (marked w + 33) = the sum of the two angles not connected to it. w and w + 1

Equation

w + w + 1 = w + 33

Solution

2w + 1 = w + 33      Subtract w from both sides.

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Step-by-step explanation:

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