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4 years ago

Identify the coefficient(s), constants, and number of terms for the following expression:

1 answer:

7 0

The given expression is: $4 x^{2} -5$

So, there are two terms in the expression
1) $4 x^{2}$
2) -5

The constant term is -5.
The co-efficient of $4 x^{2}$ is 4.

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Olivia decides to hire an electrician. The electrician charges $35 to come out to Olivia's

atroni [7]

Answer:

Step-by-step explanation:

Total cost

C (x) = 35+ 60x

Where,

Fixed cost= $35

Variable cost = 60x

x= number of hours of work

Total cost is the addition of fixed and variable cost

C (x) = 35+ 60x

C(5)= 35 + 60(5)

= 35 + 300

=335

C(5) = 335

C(5) = 335 is Olivia's total cost of hiring the electrician

x=5 is the electrician's number of hours of work

35= fixed cost of hiring the electrician

60(5) = 300 is the variable cost of hiring the electrician for 5 hours

5 0

3 years ago

I need some help please What's |5| + |–7|?

luda_lava [24]

Answer:

<h3>hello there!</h3>

$\left|5\right|+\left|-7\right|$

$rule =a,\:a\ge 0$

$|5|=5$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$\left|-7\right|=7$

$5+7=$

$12$

hope this helps you..

5 0

3 years ago

I need help with this mean, median, and averages etc. Brainliest is depending on correct answers and explanations. And don't loo

V125BC [204]

Answer:

Red is spelled as LSTER

Step-by-step explanation:

I think its a... I think its a carrot

4 0

3 years ago

One month,ruby worked 6 hours more than Isaac, and Svetlana worked 4 times as many hours as ruby. Together they worked 126 hours

Misha Larkins [42]

I + 6 = r

4r = s

i + r + s = 126

4i + 24 = 4r

s= 4r

i = r-6

4i+24=i+6
-3i=18

i = 6

Solve the rest

8 0

3 years ago

How does a set of integers differs from the set of whole numbers ? Please help

MariettaO [177]

The difference between set of whole numbers and a set of integers is that:

Whole numbers = {0, 1, 2, 3, 4, 5...}
Integers = {..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5...}

If we name contents of the first set as n, in the second set you can have 2n-1 numbers (because we count 0 only once in both sets).

7 0

3 years ago