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3 years ago

Find all real solutions of this equation to answer the question. (6 – 2x)(3 – 2x)x = 40

Mathematics

2 answers:

Vika [28.1K]3 years ago

5 0

<span>No. Its x=4. You couldn't cut the box to much lower without it being absurd.
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</span>

Readme [11.4K]3 years ago

4 0

answer:

D. No. The only real solution is x = 4. It is not possible to cut squares of this size.

hope this helps! :o)

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six friends are going to buy a pizza. Their chices are to biu 2 medium 10-inch diameter pizzas for 7:00 each, or 1 large 14 inch

11111nata11111 [884]

For this question, we want to find out the greatest amount of area of pizza for the least amount of money:

So we have two pizzas with a 10 in. diameter. Let us take one of those pizzas.

The formula for area of a circle is $\pi r ^2$ ; So the area for one of these 10 in. pizzas would be $\pi (5)^2$ or 25 $\pi$ .

We have two of these pizzas, so the total area that we would get with $14 would be 25 $\pi$ *2 or 50 $\pi$ .

For the second case, we have one pizza with a 14 in. diameter.

The area of this pizza will be $\pi (7)^2$ or 49 $\pi$ .

So for $15 we can buy 49 $\pi$ worth of pizza.

The best deal would be to buy the two medium pizzas of 10 inch diameter, because for $14, you get 50 $\pi$ .

5 0

3 years ago

6th grade math help me. :D.....

strojnjashka [21]

Question 1:
4x+28

question 2:
18x-27

4 0

3 years ago

Read 2 more answers

Seven years ago Raymond purchased a $197,000 home with a 30-year mortgage at 4.15% having recently lost his job he can no longer

tensa zangetsu [6.8K]

What’s the question ?

4 0

3 years ago

M-15=9 inverse operation

zheka24 [161]

Answer: 24

Step-by-step explanation:

m - 15 + 15 = 9 + 15

m = 24

6 0

2 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

2 years ago