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VARVARA [1.3K]
2 years ago
7

Question 6 of 10

Mathematics
1 answer:
mamaluj [8]2 years ago
4 0

Answer:

A

Step-by-step explanation:

I didn't learn jrf, but I believe that it is the amount of females that watch action movies divided by the total amount of females.

Amount of females who watch action movies= 99

Total females= 250

So, A seems correct.

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Help me please!! <br> Also explain you answer since this is a study guide for a important test!!
il63 [147K]

Answer:

<h3><em>the </em><em>answer</em><em> </em><em>is </em><em>A</em></h3>

Step-by-step explanation:

8x+6is equivalent to-7(1-x)+x+13 because

-7(1-x)+x+13

we use-7to multiply the numbers in the bracket which is equal to -7+7x(minus ❌times minus =+)

-7+7x+x+13

collect like terms

7x+x+13-7=8x+6

answer is A

6 0
2 years ago
Read 2 more answers
Point H is on line segment GI. Given GH = x + 6, HI = x + 5, and
Vaselesa [24]

Answer:

<h2>9</h2>

Step-by-step explanation:

If Point H is on line segment GI, then GH+HI = GI

Given the following parameters

GH = x + 6,

HI = x + 5, and

GI = 3x + 8

To determine the length of GH, we need to get the value of x first. To get x we will substitute the given parameters into the formula as shown;

x+6+(x+5) = 3x+8

2x+11 = 3x+8

collect like terms;

2x-3x = 8-11

-x = -3

divide both sides by -1;

-x/-1 = -3/-1

x = 3

Since GH = x+6

GH = 3+6

GH = 9

<em>Hence the numerical length of GH is 9</em>

4 0
3 years ago
If f(x)=3x-7, find f(5). *
tatiyna

Answer:

f(5) = 8

Step-by-step explanation:

3(5)-7

15-7

8

6 0
3 years ago
Read 2 more answers
Find x <br><br> please help i’ll mark the first one or whoever right brainliest
Svetllana [295]

Answer: 86

Step-by-step explanation:

4 0
2 years ago
Suppose that X ∼ Geom(p) and Y ∼ Geom(r) are independent. Find the probability P (X &lt; Y ).
Murrr4er [49]

X,Y have joint density

f_{X,Y}(x,y)=f_X(x)f_Y(y)=\begin{cases}pr(1-p)^x(1-r)^y&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

We can find P(X by integrating the joint density over the region in \Bbb R^2 where x in the first quadrant, i.e. above the line y=x:P(X

using the fact that

a^n=e^{n\ln a}\implies\displaystyle\int a^n\,\mathrm dn=\frac1{\ln a}e^{n\ln a}+C=\frac1{\ln a}a^n+C

Then using the same property,

P(X

4 0
3 years ago
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