Given F(x) = V(3x – 12) + 2, what is the range in set notation?
1 answer:
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Answer:
a. Function 1
b. Function 3
c. Function 2, Function 3 and Function 4
Step-by-step explanation:
✔️Function 1:
y-intercept = -3 (the point where the line cuts across the y-axis)
Slope, using the two points (0, -3) and (1, 2):
Slope = 5
✔️Function 2:
y-intercept = -1 (the value of y when x = 0)
Slope, using the two points (0, -1) and (1, -4):
Slope = -3
✔️Function 3: y = 2x + 5
y-intercept (b) = 5
Slope (m) = 2
✔️Function 4:
y-intercept = 2
Slope = -1
Thus, the following conclusions can be made:
a. The function's graph that is steepest is the function whose absolute value of its slope is greater. Therefore Function 1 is the steepest with slope of 5
b. Function 3 has a y-intercept of 5, which is the farthest from 0.
c. Function 2, Function 3, and Function 4 all have y-intercept that is greater than -2.
-1, 5, and 2 are all greater than -2.
Answer:
Step-by-step explanation:
we have
Line 1
Equation in slope intercept form
The slope is equal to
Line 2
Equation in slope intercept form
The slope is equal to
we know that
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)
so
substitute