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Bad White [126]
3 years ago
6

Fill in the question mark ?5

Mathematics
1 answer:
timurjin [86]3 years ago
7 0
I don't really understand your question , can you rephrase it ?

Do you mean ?5x7 = 455 ?
because then it would be :
455 divided by 7 which equals 65  :) 
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find the particular solution to the exact differentiable equation dy/dx=(2e^x)-cosx passing through the point (0,3)
lozanna [386]

Answer:

y = 2eˣ - sin x + 1  

Step-by-step explanation:

dy/dx = 2eˣ - cos x

(0, 3)

Integrate dy/dx to find the original function.

  • y = 2eˣ - sin x + C

Solve for C by substituting the point given.

  • 3 = 2e⁰ - sin(0) + C
  • 3 = 2 - 0 + C
  • 1 = C

Now we can substitute C into the original function.

  • y = 2eˣ - sin x + 1  

This is the particular, or explicit, solution to the differentiable equation.

7 0
3 years ago
A and B are two events. Which statement about the conditional probability is true?
nata0808 [166]
The answer 
by using fundamental definition
<span>The conditional probability of event B given event A is P(B|A)=P(A and B)/P(A) when two events are not independent.
so the only true answer is A, because </span>P(B|A)=P(A) if A and B are independents<span>
(definition)</span>
4 0
3 years ago
Read 2 more answers
Find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success i
Georgia [21]

Answer:

65.3%

Step-by-step explanation:

Binomial distribution PMF below (along with a description)

the probabilty of getting 2, 3, or 4 successes in 5 trials is just

p(2)+p(3)+p(4)

p(2)= 5C2*.4²*(1-.4)³ = .3456

p(3)= 5C3*.4³*(1-.4)²= .2304

p(4)= 5C4*.4⁴*(1-.4)=.0768

.3456+.2304+.0768= .6528

6 0
2 years ago
What is an equation of the line that passes through the points (4, -6)<br>and (8, -4)
QveST [7]

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{4}}}\implies \cfrac{-4+6}{4}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y+6=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x-8

3 0
3 years ago
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Make a graph of the following region 1&lt; x+y in the standard (X
artcher [175]
Slope of 1 dotted line

4 0
3 years ago
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