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3 years ago

Given that (2x-1)(x+5)=2x^2-mx-5, what is the value of m

1 answer:

3 0

Expand the left side
2x(x + 5) - 1(x + 5) = 2x² - mx - 5
2x² + 10x - x - 5 = 2x² - mx - 5
2x² + 9x - 5 = 2x² - mx - 5
cancel 2x² and -5
9x = - mx

m = -9
sorry i was wrong, my mistake hehe

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Aleksandr-060686 [28]

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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$A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|$

In this question:

Vertices (1,0) (5,0) (3,4). So

$A = \pm 0.5 \left|\begin{array}{ccc}1&0&1\\5&0&1\\3&4&1\end{array}\right|$

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3 years ago

Given that (2x-1)(x+5)=2x^2-mx-5, what is the value of m​

Given that (2x-1)(x+5)=2x^2-mx-5, what is the value of m