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3 years ago

PLEASE HELP ME TIMED!

Mathematics

1 answer:

Elena-2011 [213]3 years ago

5 0

Answer:

The ratio is 18:21 so it would be the same as 6:7. The final ratio is 126(cats):147(dogs)

Step-by-step explanation:

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A sold a commodity to b at 10% profit b again sold it to a at 10% loss. What does a have

ozzi

Let's answer this step-by-step.

First of all, let's estsblish the original price of the commodity as being 100%. Therefore:

Original price of commodity = 100%

Then, when A sold the commodity to B, it was sold at a 10% profit. Therefore:

Price of commidity when A sold to B:
100% x 1.1 = 110%

After that, when B sold it back to A, it was sold at a 10% loss. Therefore:

Price of commodity when B sold to A:
110% x 0.9 = 99%

Hence, A now has 99% of the original value of the commidity.

6 0

3 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

5 0

3 years ago

What is the simplest form of the expression (14.2a + 9.8b) – (13.1b – 0.2a) – (3.7a + 4.8b)?

Sati [7]

So, the right answer is of option A.

Look at the attached picture⤴

Hope it will help u...

8 0

3 years ago

Read 2 more answers

Plz help I need help

suter [353]

Answer:

7q + 12

Step-by-step explanation:

simply arrange the given expressions into the traditional way of adding numbers like 1 + 1 but vertically like : 1

1 +

which is equivalent to

6q + 1 +

q + 11

______

7q + 12

why? because 6q plus q is equal to 7q and 1 + 11 is equal to 12

good day.

4 0

2 years ago

8.) A line passes through the points (k, 4) and (3, -6). The line is perpendicular to

amm1812

Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

m1 = –4

–4 × m2 = – 1

Divide both side by –4

m2 = –1/–4

m2 = 1/4

Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

3 0

3 years ago